MATH SOLVE

2 months ago

Q:
# which quadratic equation is equivalent to (x^2-1)^2 -11(x^2-1)+24=0A)u^2-11u+24=0 where u=(x^2-1)B) (u^2)^2 -11(u^2) +24 where u = (x^2-1)C)u^2+1-11u+24 =0 where u =(x^2-1)D)(u^2-1)^2 -11(u^2-1) +24 where u =(x^2-1)β

Accepted Solution

A:

Answer:[tex]\large\boxed{A)\ u^2-11u+24=0}[/tex]Step-by-step explanation:[tex](x^2-1)^2 -11(x^2-1)+24=0\\\\\text{Substitute}\ (x^2-1)=u\\\\\underbrace{(x^2-1)}_{u}\ ^2 -11\underbrace{(x^2-1)}_{u}+24=0\to u^2-11u+24=0[/tex]