MATH SOLVE

3 months ago

Q:
# The owner of a 4000-gal oil truck loads the truck with gasoline and keroseno. The profit on each gallon of gasoline is 16e and on each gallon of kerosene it is 12¢. How many gallons of each fuel did the owner load itthe profit was $620?There were___gallons of gasoline and___gallons of kerosene.

Accepted Solution

A:

Answer:There were 35 gallons of gasoline and 500 gallons of kerosene.Step-by-step explanation:Step 1: Write data for equation 1Let gallons of kerosene be xLet gallons of gasoline be yTotal capacity of truck is 4000Step 2: Form equation 1x + y = 4000Step 3: Write data for equation 2Profit of total gallons of kerosene is 0.12xProfit of total gallons of gasoline is 16yTotal profit is $620Step 4: Form equation 20.12x + 16y = 620Step 5: Find x in terms of y from equation 1x + y = 4000x = 4000 - yStep 6: Substitute value of x in equation 20.12x + 16y = 6200.12 (4000 - y) + 16y = 620480 - 12y + 16y = 6204y = 620 - 480y = 140/4y = 35Step 7: Substitute value of y in equation 1 to find x0.12x + 16y = 6200.12x + 16 ( 35 ) = 6200.12x = 60x = 500There were 35 gallons of gasoline and 500 gallons of kerosene.!!